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A steel bar with diameter d = 14 mm is subjected to a tensile load P = 10 kN (see figure). (a) What is the maximum normal stress σ_{max} in the bar? (b) What is the maximum shear stress τ_{max}?

**Solution**

(a) Maximum normal stress

**σ _{x} = P / A = 10KN / ((π /4) * (14mm)^{2}) = 64.9MPa**

(b) Maximum shear stress

The maximum shear stress is on a 45^{o} plane and equals σ_{x} / 2.

**τ _{max} = σ_{max} / 2 = 64.9MPa / 2 = 32.45MPa**

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