A pressure-vessel head is fabricated by gluing the circular plate to the end of the vessel. If the vessel sustains an internal pressure of 500 kPa, determine the average shear stress in the glue.
The force that is normal to the vessel’s head is P = τανg(2π)(0.225) * (0.01) where τανg is the average shear stress.
SFy = 0 -> π(0.225)2*500*103 - τανg(2π)(0.225)*(0.01) = 0
τανg = 11.25Mpa
Based on Figure 1, we get: where:...
The rod of the picture is loaded with the force 2...