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Torsional Moment-Stress
This calculation is an example problem in structural engineering. This content is sponsored by PPI. For exam preparation courses on FE and PE, see the list offered by PPI
Calculate the max stress because of torsional moment on the outer layer of a steel hollow rod when two forces act on it from a distance of 50mm from the center.
Solution
T = 300KN * 0.1 = 30KNm
Polar moment of inertia for hollow rod.
J = (π/2) * (R42 - R41) = (3.14/2) * (0.0254 - 0.0104) = 5.976 * 10-7m4
Maximum stress at the outer layer.
tmax = (T * R2) / J = (30KNm * 0.025m) / (5.976 * 10-7m4) = 1.255E + 6 N/m2
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