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**Calculate the max stress because of torsional moment on the outer layer of a steel hollow rod when two forces act on it from a distance of 50mm from the center.**

**Solution**

T = 300KN * 0.1 = 30KNm

Polar moment of inertia for hollow rod.

J = (π/2) * (R^{4}_{2} - R^{4}_{1}) = (3.14/2) * (0.025^{4} - 0.010^{4}) = 5.976 * 10^{-7}m^{4}

Maximum stress at the outer layer.

t_{max} = (T * R_{2}) / J = (30KNm * 0.025m) / (5.976 * 10-7m^{4}) = 1.255E + 6 N/m^{2}

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