Bentley's Bentley Coffee Corner: Structural SEAPAC - Integrated Connection Design using STAAD.Pro and RAM Connection begins at 18 Aug 2022
Bentley's Bentley Coffee Corner: Structural SEAPAC - Integrated Connection Design using STAAD.Pro and RAM Connection begins at 18 Aug 2022
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The friction coefficient is c1=0.2 between two bodies A,B. The friction coefficient is c2=0.18 between body B and the ground. If mass mA=0.5kgr and mB=1kgr , what is the minimum force P so that the two bodies start sliding?(we consider that there is no friction at the rope).
Solution
If T1 is the friction force for A, the equilibrium for the body A is
ΣFX=0→T1-F1=0 (1)
ΣFY=0→N1-mA*g=0 (2)
And because the body A starts to move
T1=c1*N1 (3)
For the body B the equilibrium is
ΣFX=0→P-F-T1-T2=0 (4)
ΣFY=0→N2-mA*g-N1=(5)
And because the body B starts to move
T2=c2*N2 (6)
With the acceleration of gravity g=10m/sec2
We solve (1),(2),(3),(4),(5),(6)
P=4.7N
Selected Topics
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